Talk:Superfunction

Superfunction evaluated *at point t*

I seem to not to become familiar with the concept of Superfunctions. But I understand now at least one reason. If we say "F(z) = f(f(f(...f(t))), where f is evaluated z times" then we obscure, that we evaluate f initially *at the point t*. That means, for each *t* we have another superfunction! So a) we should notice that in the article (I couldn't make the change, don't know why) and b) should change the notation, to something like "F_t(z) = f(f(f(...f(t))), where f is evaluated z times beginning at t".

We'll see then, that the range of the "superfunction at some t" is limited to intervals around t between fixpoints and that "F_t(z)" cannot exceed that intervals by change of the parameter z (as long as z is real, there is one option for complex z to step to a neighboured interval). An example is "f(t)=2^t-1 ", whose superfunction -if evaluated beginning at any value "0<t<1" - cannot exceed this range.

--Gottfried Helms 06:50, 24 November 2011 (UTC)