Superfunction: Difference between revisions

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imported>Dmitrii Kouznetsov
(try to fix problem with math in preamble)
 
imported>Dmitrii Kouznetsov
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'''Superfunction''' is smooth exstension of iteration of other function for the case of non-integer number of iterations.
'''Superfunction''' is smooth exstension of iteration of other function for the case of non-integer number of iterations.
===Routgly===
Roughly, if, for some constant <math>t</math>,
Roughly, if <math>S(z)=f(f(...f(a)))</math>
:<math> {{S(z)} \atop \,}  {= \atop \,} 
{{\underbrace{f\Big(f\big(... f(t)...\big)\Big)}} \atop {z \mathrm{~evaluations~of~function~}f\!
\!\!\!\!\!}}</math>
then <math>S</math> can be interpreted as superfunction of function <math>f</math>.
Such definition is valid only for positive integer <math>z</math>.
<!--  In particular, :<math>S(1)=f(t)</math> !-->


<math> {{a + b} \atop \,}  {= \atop \,} {a  \, + \atop \, } {{\underbrace{1 + 1 + \cdots + 1}} \atop b}</math>
==Extensions==
The recurrence above can be written as equations
:<math>S(z\!+\!1)=f(S(z)) ~ \forall z\in \mathbb{N} : z>0</math>
:<math>S(1)=f(t)</math>.
Instead of the last equation, one could write
:<math>S(0)=f(t)</math>
and extend the range of definition of superfunction <math>S</math> to the non-negative integers.
Then, one may postulate
:<math>S(-1)=t</math>
and extend the range of validity to the integer values larger than <math>-2</math>.
The following extension, for example,
:<math>S(-2)=f^{-1}(t)</math>
is not trifial, because the inverse function may happen to be not defined for some values of <math>t</math>.
In particular, [[tetration]] can be interpreted as super-function of exponential for some real base <math>b</math>; in this case,
<!-- :<math>f(z)={b}^z</math>!-->
:<math>f=\exp_{b}</math>
then, at <math>t=0</math>,
:<math>S(-1)=\log_b(1)=0 </math>.
but
:<math>S(-2)=\log_b(0)~ \mathrm{is~ not~ defined}</math>.


<math> {S(z) \atop \,}  {= {{\underbrace{f\Big  (t)\Big}} \atop {z {\rm ~evaluations~ of~ function~}f } }</math>
For extension to non-integer values of the argument, superfunction should be defined in different way.
 
<math>{S(z)~=~ \atop {~}
{\underbrace{\exp_a\!\Big(\exp_a\!\big(...\exp_a(t) ... )\big)\Big)} \atop ^{z ~\rm exponentials}}
<math>
==Definition==
==Definition==
For complex numbers <math>~a~</math> and <math>~b~</math>, such that <math>~a~</math> belongs to some domain <math>D\subseteq \mathbb{C}</math>,<br>
For complex numbers <math>~a~</math> and <math>~b~</math>, such that <math>~a~</math> belongs to some domain <math>D\subseteq \mathbb{C}</math>,<br>
Line 17: Line 37:
:<math>S(z\!+\!1)=f(S(z)) ~ \forall z\in D : z\!+\!1 \in D</math>
:<math>S(z\!+\!1)=f(S(z)) ~ \forall z\in D : z\!+\!1 \in D</math>
:<math>S(a)=b</math>.
:<math>S(a)=b</math>.
==Examples==
==Examples==
===Addition===
===Addition===

Revision as of 22:35, 8 December 2008

Superfunction is smooth exstension of iteration of other function for the case of non-integer number of iterations. Roughly, if, for some constant ,

then can be interpreted as superfunction of function . Such definition is valid only for positive integer .

Extensions

The recurrence above can be written as equations

.

Instead of the last equation, one could write

and extend the range of definition of superfunction to the non-negative integers. Then, one may postulate

and extend the range of validity to the integer values larger than . The following extension, for example,

is not trifial, because the inverse function may happen to be not defined for some values of . In particular, tetration can be interpreted as super-function of exponential for some real base ; in this case,

then, at ,

.

but

.

For extension to non-integer values of the argument, superfunction should be defined in different way.

Definition

For complex numbers and , such that belongs to some domain ,
superfunction (from to ) of holomorphic function on domain is function , holomorphic on domain , such that

.

Examples

Addition

Chose a complex number and define function with relation . Define function with relation .

Then, function is superfunction ( to ) of function on .

Multiplication

Exponentiation is superfunction (from 1 to ) of function .

Abel function

Inverse of superfunction can be interpreted as the Abel function.

For some domain and some ,,
Abel function (from to ) of function with respect to superfunction on domain is holomorphic function from to such that

The definitionm above does not reuqire that ; although, from properties of holomorphic functions, there should exost some subset such that . In this subset, the Abel function satisfies the Abel equation.

Abel equation

The Abel equation is some equivalent of the recurrent equation

in the definition of the superfunction. However, it may hold for from the reduced domain .


Applications of superfunctions and Abel functions