Talk:Slater orbital: Difference between revisions

From Citizendium
Jump to navigation Jump to search
imported>David E. Volk
(suggest explain position probability & normalization integral equals 1?)
imported>Paul Wormer
No edit summary
Line 18: Line 18:


[[User:David E. Volk|David E. Volk]] 13:30, 9 October 2007 (CDT)
[[User:David E. Volk|David E. Volk]] 13:30, 9 October 2007 (CDT)
Hi David, I'm not sure I follow you completely. But as a reaction, I wrote out the normalization more explicit, and pointed out that the angular part is also normalized. As I understand you, you like to point out that the absolute square of a one-electron wave function is a probability of finding an electron at certain position? I have two objections to adding this: (1) A Slater orbital is not (yet) a wave function (is not a solution of the Sch Eq) and (2) such a remark belongs to the quantum mechanics article and does not have to be repeated over and over  in quantum mechanically oriented articles. But then again, maybe I misunderstand you. Cheers, --[[User:Paul Wormer|Paul Wormer]] 02:39, 10 October 2007 (CDT)

Revision as of 01:39, 10 October 2007


Article Checklist for "Slater orbital"
Workgroup category or categories chemistry Workgroup, physics Workgroup [Please add or review categories]
Article status Developing article: beyond a stub, but incomplete
Underlinked article? Yes
Basic cleanup done? No
Checklist last edited by --Paul Wormer 04:15, 22 August 2007 (CDT)

To learn how to fill out this checklist, please see CZ:The Article Checklist.





From WP (corrected and mainly written by me).--Paul Wormer 04:15, 22 August 2007 (CDT)

Paul, in the derivation of the normalization constant, perhaps you should explain how the normalization factor works, ie the sum of probably must add up to one, and the probability of being at any one point is ....

thus the integral equation over all space being equal to one.

David E. Volk 13:30, 9 October 2007 (CDT)

Hi David, I'm not sure I follow you completely. But as a reaction, I wrote out the normalization more explicit, and pointed out that the angular part is also normalized. As I understand you, you like to point out that the absolute square of a one-electron wave function is a probability of finding an electron at certain position? I have two objections to adding this: (1) A Slater orbital is not (yet) a wave function (is not a solution of the Sch Eq) and (2) such a remark belongs to the quantum mechanics article and does not have to be repeated over and over in quantum mechanically oriented articles. But then again, maybe I misunderstand you. Cheers, --Paul Wormer 02:39, 10 October 2007 (CDT)