Fibonacci number: Difference between revisions
Jump to navigation
Jump to search
imported>Aleksander Stos m (not sure whether it should be left in the article (in the present form)) |
imported>Aleksander Stos (→Direct formula: straightforward claim of the formula) |
||
Line 23: | Line 23: | ||
== Direct formula == | == Direct formula == | ||
We have | |||
:<math>F_n\ =\ \frac{1}{\sqrt{5}}\cdot \left(\left(\frac{1+\sqrt{5}}{2}\right)^n - \left(\frac{1-\sqrt{5}}{2}\right)^n\right)</math> | |||
for every <math>\ n=0,1,\dots</math> . | |||
Indeed, let <math>A := \frac{1+\sqrt{5}}{2}</math> and <math>a := \frac{1-\sqrt{5}}{2}</math> . Let | |||
:<math>f_n\ :=\ \frac{1}{\sqrt{5}}\cdot(A^n - a^n)</math> | |||
Then: | Then: | ||
Line 34: | Line 37: | ||
* <math>f_{n+2}\ =\ f_{n+1}+f_n</math> | * <math>f_{n+2}\ =\ f_{n+1}+f_n</math> | ||
for every <math>\ n=0,1,\dots</math>. Thus <math>\ f_n = F_n</math> for every <math>\ n=0,1,\dots</math> | for every <math>\ n=0,1,\dots</math>. Thus <math>\ f_n = F_n</math> for every <math>\ n=0,1,\dots,</math> and the formula is proved. | ||
Furthermore, we have: | |||
* <math>A\cdot a = -1\ </math> | * <math>A\cdot a = -1\ </math> | ||
Line 44: | Line 45: | ||
* <math>-1 < a < 0\ </math> | * <math>-1 < a < 0\ </math> | ||
* <math>\frac{1}{2}\ >\ \left|\frac{1}{\sqrt{5}}\cdot a^n\right|\quad\rightarrow\quad 0</math> | * <math>\frac{1}{2}\ >\ \left|\frac{1}{\sqrt{5}}\cdot a^n\right|\quad\rightarrow\quad 0</math> | ||
It follows that | It follows that | ||
:<math>F_n\ </math> is the nearest integer to <math>\frac{1}{\sqrt{5}}\cdot \left(\frac{1+\sqrt{5}}{2}\right)^n</math> | :<math>F_n\ </math> is the nearest integer to <math>\frac{1}{\sqrt{5}}\cdot \left(\frac{1+\sqrt{5}}{2}\right)^n</math> | ||
Revision as of 09:31, 29 December 2007
In mathematics, the Fibonacci numbers form a sequence defined by the following recurrence relation:
The sequence of fibonacci numbers start: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, ...
Properties
- The quotient of two consecutive fibonacci numbers converges to the golden ratio:
- If divides then divides
- If and is a prime number then is prime. (The converse is false.)
Direct formula
We have
for every .
Indeed, let and . Let
Then:
- and
- hence
- hence
for every . Thus for every and the formula is proved.
Furthermore, we have:
It follows that
- is the nearest integer to
for every . It follows that ; thus the value of the golden ratio is
- .
Further reading
- John H. Conway und Richard K. Guy, The Book of Numbers, ISBN 0-387-97993-X
Applications
The sequence of Fibonacci numbers was first used to represent the growth of a colony of rabbits, starting with one pair of rabbits.