Haber process: Difference between revisions
imported>Oliver Smith (→[[Electrolysis of water]]: Added state symbols) |
imported>Oliver Smith (→[[Electrolysis of water]]: Emphasised that the water is electrolysed) |
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2O<sup>2-</sup> → O<sub>2 (g)</sub> | 2O<sup>2-</sup> → O<sub>2 (g)</sub> | ||
For every two electrons passed, 2 hydrogen ions form a molecule of hydrogen gas at the cathode, but another 2 hydrogen ions are formed at the anode. The sulphate ions stay in solution throughout the reaction, meaning that overall, the amount of sulphuric acid remains constant, and the water is electrolysed: | For every two electrons passed, 2 hydrogen ions form a molecule of hydrogen gas at the cathode, but another 2 hydrogen ions are formed at the anode. The sulphate ions stay in solution throughout the reaction, meaning that overall, the amount of sulphuric acid remains constant, and it is the water that is electrolysed: | ||
4H<sup>+</sup> + 2H<sub>2</sub>O <sub>(l)</sub> → 2H<sub>2 (g)</sub> + O<sub>2 (g)</sub> + 4H<sup>+</sup> | 4H<sup>+</sup> + 2H<sub>2</sub>O <sub>(l)</sub> → 2H<sub>2 (g)</sub> + O<sub>2 (g)</sub> + 4H<sup>+</sup> |
Revision as of 05:33, 25 May 2007
The Haber process is a process used to produce the useful substance ammonia from nitrogen and hydrogen.
Sources of gases
Hydrogen
Hydrogen is only found in the air in the form of water vapour, as if there was more hydorgen gas, it would react with the oxygen, forming water. However, the reverse reaction can be used to form hydrogen: the electrolysis of water. Also, a fuel processor can be used to extract the hydrogen from methane (natural gas).
Electrolysis of water
Pure water is a poor conductor of electricity, so often a soluble ionic compound is added, such as an acid, base or salt. Sulphuric acid (H2SO4) is often used because it is fully dissociated when dissolved in water, and is difficult to oxidise, so oxygen gas will form at the anode.[1].
Only some water molecules form an oxide and a hydroxide ion, meaning that water is only partially ionised and hence a poor conductor of electricity.
H2O (l) → H+ + OH-
Sulphuric acid, on the other hand, is fully ionised when dissolved in water:
H2SO4 (aq) → 2H+ + SO42-
Once electrolysis has begun, the hydrogen ions move towards the cathose where they are reduced to form hydrogen gas:
2H+ + 2e- → H2 (g)
At the anode, the water splits into two oxygen ions which form a covalent bond, and are relased as oxygen gas. Two hydrogen ions are also produced:
H2O → O2- + 2H+ + 2e-
2O2- → O2 (g)
For every two electrons passed, 2 hydrogen ions form a molecule of hydrogen gas at the cathode, but another 2 hydrogen ions are formed at the anode. The sulphate ions stay in solution throughout the reaction, meaning that overall, the amount of sulphuric acid remains constant, and it is the water that is electrolysed:
4H+ + 2H2O (l) → 2H2 (g) + O2 (g) + 4H+
Or, more simply:
2H2O (l) → 2H2 (g) + O2 (g)
Reaction
N2 (g) + H2 (g) -> NH3 (g)